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Stoichiometric Calculations

The minimum a...

Question

The minimum amount of $A g_{2} C O_{3} (s)$ required to produce sufficient oxygen for the complete combustion of $C_{2} H_{2}$ which produces $11.2 L$ of $C O_{2}$ at STP after combustion is:
(Molar mass of $A g = 108 g/mol$ )
$A g_{2} C O_{3 (s)} \to 2 A g_{(s)} + C O_{2 (g)} + \frac{1}{2} O_{2 (g)}$
$C_{2} H_{2} + \frac{5}{2} O_{2} \to 2 C O_{2} + H_{2} O$

A

276 g

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B

345 g

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C

690 g

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D

138 g

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Solution

The correct option is B $345 g$
$A g_{2} C O_{3 (s)} \to 2 A g_{(s)} + C O_{2 (g)} + \frac{1}{2} O_{2 (g)} (1)$

$C_{2} H_{2} + \frac{5}{2} O_{2} \to 2 C O_{2} + H_{2} O (2)$

11.2 litre of $C O_{2}$ at STP = $\frac{11.2}{22.4} = 0.5 mol of C O_{2}$

From equation (2), 2 mol of $C O_{2}$ is produced from 2.5 mol of $O_{2}$ .
$∴$ 0.5 mol of $C O_{2}$ will be formed from = $\frac{2.5}{2} \times 0.5$ = 0.625 mol of $O_{2}$ .
From equation (1),
1 mol of $A g_{2} C O_{3}$ produces 0.5 mol of $O_{2}$ .
0.625 mol of $O_{2}$ is formed from = $0.625 \times 2$ = 1.25 mol of $A g_{2} C O_{3}$ .

Molar mass of $A g_{2} C O_{3} = 276 {g mol}^{- 1}$
$∴$ Minimum amount of $A g_{2} C O_{3} required = 276 g/mol \times 1.25 mol = 345 g$

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Similar questions

Q. The minimum amount of

A g_{2} C O_{3} (s)

required to produce sufficient oxygen for the complete combustion of

C_{2} H_{2}

, which produces

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at STP after combustion is:

[A g = 108]

A g_{2} C O_{3} (s) \to 2 A g (s) + C O_{2} (g) + \frac{1}{2} O_{2} (g)

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The minimum amount of $A g_{2} C O_{3} (s)$ required to produce sufficient oxygen for the complete combustion of $C_{2} H_{2}$ , which produces $11.2 L$ of $C O_{2}$ at STP after combustion is: $[A g = 108]$

$A g_{2} C O_{3} (s) \to 2 A g (s) + C O_{2} (g) + \frac{1}{2} O_{2} (g)$

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Q. Minimum amount of

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C_{2} H_{2} + 5 / 2 O_{2} \to 2 C O_{2} + H_{2} O

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