The minimum and maximum values of f x - x 2-4 x -17 areA- 25 and 82B- 13 and -C- 17 and 82D- 15 and -

The correct option is B 13 and f(x) = x^2 + 4x + 17 a = 1, b = 4, c = 17 As a gt; 0, minimum value = D/4a = 4ac b^2/4a = c b^2/4a = 17 4 = 13 Graph ...

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Standard XII

Mathematics

Real Valued Functions

The minimum a...

Question

The minimum and maximum values of $f (x) = x^{2} + 4 x + 17$ are

17 and 82

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15 and

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13 and

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25 and 82

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Solution

The correct option is C
13 and

$f (x) = x^{2} + 4 x + 17$

a = 1, b = 4, c = 17

As a > 0, minimum value = $\frac{- D}{4 a}$

$= \frac{4 a c - b^{2}}{4 a}$

$= c - \frac{b^{2}}{4 a}$

= 17 - 4 = 13

Graph of f(x) will be upward parabola with minimum value 13

So, maximum value is $\infty$

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The minimum and maximum values of f(x)=x2+4x+17 are

The correct option is C 13 and f(x)=x2+4x+17 a = 1, b = 4, c = 17 As a > 0, minimum value = −D4a =4ac−b24a =c−b24a = 17 - 4 = 13 Graph of f(x) will be upward parabola with minimum value 13 So, maximum value is ∞

The minimum and maximum values of $f (x) = x^{2} + 4 x + 17$ are

The correct option is C
13 and

$f (x) = x^{2} + 4 x + 17$

a = 1, b = 4, c = 17

As a > 0, minimum value = $\frac{- D}{4 a}$

$= \frac{4 a c - b^{2}}{4 a}$

$= c - \frac{b^{2}}{4 a}$

= 17 - 4 = 13

Graph of f(x) will be upward parabola with minimum value 13

So, maximum value is $\infty$