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Applying NLM along 3 Axis

The minimum a...

Question

The minimum area of main steel (in $m m^{2}$ ) (Fe415) for the given beam section is

282

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Solution

The correct option is A 282
The minimum area of longitudinal steel is specified in IS 456 : 2000 to avoid sudden failure of beam at cracking moment. Minimum steel is given by.

$\frac{A s t_{m i n}}{b d} = \frac{0.85}{f_{y}}$

$A s t_{m i n} = \frac{0.85}{415} \times 300 \times 460 = 282.65 m m^{2}$

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