Question

The minimum energy required to dissociate $Ag$ $Br$ bond in 0.6 $eV$. A photographic flim is coated with a sliver bromide layer. Find the maximum wavelength whose signature can be recorded on the film

• A. 207 $nm$
• B. 702 $nm$
• C. 207 $A^{\circ }$
• D. 2070 $nm$

Answer 1

The correct option is D 2070 $nm$

We have

$E=\frac{1240}{\lambda }eV$

$⟹\lambda =\frac{1240}{E}=\frac{1240}{0.6}=2070nm$

So, the answer is option (D).