Question

The minimum horizontal acceleration of the container so that the pressure at point A of the container becomes atmospheric is (the tank is of sufficient height)

• A. $\frac{3}{2}g$
• B. $\frac{4}{3}g$
• C. $\frac{4}{2}g$
• D. $\frac{3}{4}g$

Answer 1

The correct option is B

$\frac{4}{3}g$

Volume equality gives

$2\times 3=\frac{1}{2}\times h\times 3\Rightarrow 4m$

$\therefore tan\theta =\frac{4}{3}=\frac{a}{g}\Rightarrow a=\frac{4}{3}g$