The minimum initial speed of the bullet, if the block and the bullet are to successfully execute a complete ride on the loop, is:
A
3√gR
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B
3√5gR
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C
5√gR
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D
5√3gR
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Solution
The correct option is B3√5gR
When the bullet of mass 'm' hits the block of mass '2m', the total mass becomes 3m. and we know that if a particle of any mass wants to complete a circle then it should have a minimum speed of √5gR. It means that bullet plus block mass system has a minimum velocity of √5gR at the lowermost point. Now, we can apply the law of conservation of linear momentum. we have mv0=(m+2m)√5gR⇒v0=3√5gR