The correct option is B -11
x−2x+5>2⇒x−2x+5−2>0⇒x−2−2(x+5)x+5>0⇒x−2−2x−10x+5>0⇒−(x+12)x+5>0⇒x+12x+5<0x+12 >0 and x+5<0⇒x>−12 and x <−5 ORx+12 <0 and x+5>0⇒x<−12 and x >−5(This is not possible)Hence, x>−12 and x<−5.Minimum integral value of x satisfying the given inequality is −11.