The minimum number of carbon atoms an alkyne must have to show diastereomerism is:
A
4
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B
5
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C
6
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D
7
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Solution
The correct option is C 5 To show diastereoisomerism, an alkyne should have a minimum of 5 carbon atoms. This will result in the formation of cis and trans isomers which can also be designated as Z and E isomers.