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Question

The minimum pH required to prevent the precipitation of ZnS in a solution containing 0.01 M ZnCl2 and saturated with 0.10 MH2S is


(Given Ksp(ZnS)=1021,Ka1×Ka2ofH2S=1020)




A
1
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B
7
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C
2
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D
4
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Solution

Step 1:

To prevent ionic product of ions should not exceed Ksp.

So, [S2]=Ksp[Zn2+]=1021102=1019

Step 2:

H2S2H++S2

Ka=[H+]2[S2][H2S]

[H+]2=0.01as[H+]=0.1M

So, pH = 1

Hence, option (D) is correct.


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