The minimum pressure require to force the blood of density 1.04 g cm^-3 from the heart to the top of the head (vertical distance = 60 cm) is:

5.1 x 10⁴ dyne cm^-2

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6 x 10⁵ dyne cm^-2

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6.1 x 10⁴ dyne cm^-2

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3.5 x 10⁴ dyne cm^-2

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Solution

The correct option is C
6.1 x 10⁴ dyne cm^-2

According to Bernoulli’s theorem

P₁- P₂ = r g (h₂-h₁) + ½ r (v₂²– v₁²)

If v₂ = v₁, then

P₁- P₂ = r g (h₂-h₁)

= 1.04 x 981 x 60 dyne cm^-2

= 6.1 dyne cm^-2

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The minimum pressure require to force the blood of density 1.04 g cm-3 from the heart to the top of the head (vertical distance = 60 cm) is:

The correct option is C 6.1 x 104 dyne cm-2 According to Bernoulli’s theorem P1- P2 = r g (h2-h1) + ½ r (v22– v12) If v2 = v1, then P1- P2 = r g (h2-h1) = 1.04 x 981 x 60 dyne cm-2 = 6.1 dyne cm-2

The minimum pressure require to force the blood of density 1.04 g cm^-3 from the heart to the top of the head (vertical distance = 60 cm) is:

The correct option is C
6.1 x 10⁴ dyne cm^-2

According to Bernoulli’s theorem

P₁- P₂ = r g (h₂-h₁) + ½ r (v₂²– v₁²)

If v₂ = v₁, then

P₁- P₂ = r g (h₂-h₁)

= 1.04 x 981 x 60 dyne cm^-2

= 6.1 dyne cm^-2