1
Question
The minimum quantities of water supplied to three tanks are given below. What will be the total quantity of water in mL? Hint: 1 L = 1,000 mL
Tank 1
Tank 2
Tank 3
Quantity (in L)
55
67
83
Quantity (in mL)
The minimum quantities of water supplied to three tanks are given below. What will be the total quantity of water in mL? Hint: 1 L = 1,000 mL
|
Tank 1 |
Tank 2 |
Tank 3 |
|
|
Quantity (in L) |
55 |
67 |
83 |
|
Quantity (in mL) |
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Solution
The correct option is C 205,000 mL
Tank 1 = 55 L
Tank 2 = 67 L
Tank 3 = 83 L
- 1 L=1,000 mL
- To get the quantity in mL, multiply 55 L with 1,000 (as 1 L=1,000 mL).
- For a tank 1: 55×1,000=55,000 mL.
- Thus, there are 55,000 mL in 55 L.
- To get the quantity in mL, multiply 67 L with 1,000(as 1 L=1,000 mL)/.
- For a tank 2: 67×1,000=67,000 mL.
- Thus, there are 67,000 mL in 67 L.
- To get the quantity in mL, multiply 83 L with 1,000(as 1 L=1,000 mL).
- For a tank 3: 83×1,000=83,000 mL.
- Thus, there are 83,000 mL in 83 L.
- So the total quantity is the sum of the quantities of water in three tanks =55,000 mL+67,000 mL+83,000 mL =205,000 mL
Hence, the total quantity of water in mL = 205,000 mL.
Tank 1 = 55 L
Tank 2 = 67 L
Tank 3 = 83 L
- 1 L=1,000 mL
- To get the quantity in mL, multiply 55 L with 1,000 (as 1 L=1,000 mL).
- For a tank 1: 55×1,000=55,000 mL.
- Thus, there are 55,000 mL in 55 L.
- To get the quantity in mL, multiply 67 L with 1,000(as 1 L=1,000 mL)/.
- For a tank 2: 67×1,000=67,000 mL.
- Thus, there are 67,000 mL in 67 L.
- To get the quantity in mL, multiply 83 L with 1,000(as 1 L=1,000 mL).
- For a tank 3: 83×1,000=83,000 mL.
- Thus, there are 83,000 mL in 83 L.
- So the total quantity is the sum of the quantities of water in three tanks =55,000 mL+67,000 mL+83,000 mL =205,000 mL
Hence, the total quantity of water in mL = 205,000 mL.
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