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Question

The minimum quantity of H2S needed to precipitate 63.5 g of Cu2+ will be nearly -

A
63.5 g
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B
31.75 g
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C
34.0 g
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D
2.0 g
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Solution

The correct option is C 34.0 g
Meq. of H2S= Meq. of Cu2+
WH2S34.0/2×1000=63.563.5/2×1000
WH2S=34.0 g
Hence, (c) is the correct answer.

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