The minimum speed of a bucket full of water whirled in a vertical circle of radius $10 m$ at the highest point so that the water may not fall $(g = 10 {m s}^{- 2})$

1 m s^{- 1}

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2 m s^{- 1}

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5 m s^{- 1}

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10 m s^{- 1}

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Solution

The correct option is D $10 m s^{- 1}$
At the highest point the minimum speed should be equal to $\sqrt{r g}$
here $r = 10 m, g = 10 m / s^{2}$
$⟹ v = \sqrt{10 * 10} = 10 m / s$

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The minimum speed of a bucket full of water whirled in a vertical circle of radius 10 m at the highest point so that the water may not fall (g=10ms−2)

The correct option is D 10 ms−1At the highest point the minimum speed should be equal to √rghere r=10m,g=10m/s2⟹v=√10∗10=10m/s

The minimum speed of a bucket full of water whirled in a vertical circle of radius $10 m$ at the highest point so that the water may not fall $(g = 10 {m s}^{- 2})$

The correct option is D $10 m s^{- 1}$
At the highest point the minimum speed should be equal to $\sqrt{r g}$
here $r = 10 m, g = 10 m / s^{2}$
$⟹ v = \sqrt{10 * 10} = 10 m / s$