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Question

The minimum value of 2x2+x−1 is :

A
14
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B
32
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C
98
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D
94
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Solution

The correct option is C 98
f(x)=2x2+x1
Differentiating the above function with respect to x.
f(x)=4x+1
=0
Or
4x+1=0
x=14.
Now
f′′(x)=4
or
f′′(x)x=14>0
Hence the function attains a minimum value at x equal to -0.25.
Therefore
f(14)=2(116)141
=18141
=182888
=98

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