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B
32
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C
−98
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D
94
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Solution
The correct option is C−98 f(x)=2x2+x−1 Differentiating the above function with respect to x. f′(x)=4x+1 =0 Or 4x+1=0 x=−14. Now f′′(x)=4 or f′′(x)x=−14>0 Hence the function attains a minimum value at x equal to -0.25. Therefore f(−14)=2(116)−14−1 =18−14−1 =18−28−88 =−98