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Question

The minimum value of 3cosx+4sinx+5 is

[MNR 1991]


A

5

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B

9

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C

7

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D

0

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Solution

The correct option is D

0


The minimum value of 3 cos x + 4 sin x is -32+42 = -5

Hence the minimum value of 3 cos x + 4 sin x + 5

= -5 + 5 = 0


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