The minimum value of $4 e^{x} + 9 e^{- X}$ is

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Solution

The correct option is C 12
use AM & GM
$\frac{4 e^{x} + 9 e^{- x}}{2} \geq (4 e^{x} \times 9 e^{- x})^{\frac{1}{2}}$
$4 e^{x} + 9 e^{- x} \geq 12$

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