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Question

The minimum value of 4x28x+7, is

A
3
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B
4
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C
5
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D
6
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Solution

The correct option is B 3
The minimum value of f(x)=4x28x+7
Differentiating it with respect to x
8x=8
x=1
The coefficient of x2 is 4
Therefore , it is upward parabola with minimum value at x=1
Minimum value =48+7=3

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