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Question

The minimum value of F such that the block is at rest is (tanθ>μ.)
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A
mg(sinθμ cosθ)
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B
mg(sinθ+μ cosθ)
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C
mg(tanθμ sinθ)
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D
mg(cosθμ sinθ)
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Solution

The correct option is A mg(sinθμ cosθ)
For minimum value of F friction will act upward to the plane
So
F+f=mgsinθ
F=mgsinθf
For minimum value of F friction should be limiting
So
F=mgsinθμmgcosθ
F=mg(sinθμgcosθ)

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