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Question

The minimum value of XY+YZ+3ZX for all positive real numbers x, y, z is

A
313.212
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B
223.312
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C
212.323
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D
213.312
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Solution

The correct option is B 223.312
XY+YZ+3ZX
Consider six positive real numbers XY,12YZ,12YZ,133zx,133zx
XY+12YZ+12YZ+133zx+133zx66XY×12YZ×12YZ×133zx×133zx
XY+YZ+3zz6×6XY×YZ×ZX×12×2×3×3×3
XY+YZ+3zz6622×33
2×3213×312
223×312
Hence, the correct answer is option (2).

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