The minimum value of funciton $y = x^{2}$ in the interval $[1, 5]$

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Solution

The correct option is B $1$
Given, $y = x^{2}$
$\frac{d y}{d x} = 2 x > 0, \forall x ϵ [1, 5]$
$y$ is increasing in the interval $[1, 5]$
$∴ y_{m i n} = (1)^{2} = 1$

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