Question

The minimum value of $x^2-8x+17$ is

• A. 17
• B. -1
• C. 1
• D. 2

Answer 1

The correct option is C 1

$f^{\prime }\left(x\right)=2x-8$
$f^{\prime }\left(x\right)=0$ at $x=4$
$f^{\prime }\left(x\right)<0$ for $x<4$
$f^{\prime }\left(x\right)>0$ for$x>4$
$f\left(x\right)$ is minimum at $x=4$
$f\left(4\right)=1$