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Question

The minimum value of |sinx+cosx+tanx+secx+cosecx+cotx| is

A
221
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B
22+1
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C
21
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D
2+1
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Solution

The correct option is B 221
Let sinx+cosx=t , we get t21=sin2x
Let P=|sinx+cosx+tanx+cotx+cosecx+secx|=|t+1+tsinxcosx|=|t+2t1|
t=2sin(x+45)
If p=12 , then P=221
Therefore the minimum value is 221

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