The minimum value of the expression; a+1a;a>0 is:
Soln:
a+1a=(√a−1√a)2+2
For minimum value of a+1a ,we want minimum value of (√a−1√a)2 that will be zero.
So, minimum value of a+1a will be 2. Hence option (b)
2nd method:- By, A.M ≥ G.M a+1a2≥√(a×1a thus a+1a>2 (i.e.,)(a+1a)min will be 2 . option (b).