wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The minimum value of the expression f(x)=x2+4x+17 for real value of x is

A
17
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
13
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
21
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 13
The Minimum value of the expression f(x)=x2+4x+17 is

4acb24a=4(1)(17)(4)24(1)=68164=524=13

Option B is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Extrema
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon