The minimum value of the expression is y=|x+1|+|x−3| is
A
0
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B
1
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C
4
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D
5
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Solution
The correct option is C4 y=|x+1|+|x−3| Here the turning points are −1,3 y=⎧⎨⎩−(x+1)−(x−3),x<−1(x+1)−(x−3),−1≤x<3(x+1)+(x−3),x≥3⇒y=⎧⎨⎩2−2x,x<−14,−1≤x<32x−2,x≥3