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Question

The minimum value of x2+11+x2 occurs at

A
x=0
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B
x=1
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C
x=4
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D
x=3
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Solution

The correct option is A x=0
Let f(x)=x2+11+x2
On differentiating w.r.t. x, we get f(x)=2x1(1+x2)22x
For a minimum, put f(x)=0
2x((1+x2)21(1+x2)2)=0
x=0

So, the function has the minimum value at x=0

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