Minimum value of |x−6|+|x+3|+|x−8|+|x+4|+|x−3| i.e.
Sum of absolute values of deviations of observation x will be minimum, when it's value is taken about median of observations −4,−3,3,6,8
∵Median =3
So after substituting x=3 in |x−6|+|x+3|+|x−8|+|x+4|+|x−3|
We get |3−6|+|3+3|+|3−8|+|3+4|+|3−3|
=3+6+5+7+0=21