Question

The minimum value of $x^2$, if $x\in \left(-3,5\right]$ is

• A. \N
• B. 9
• C. -9
• D. 4

Answer 1

The correct option is A \N

$\therefore x\in \left(-3,5\right]\Rightarrow -3\le x\le 5x^2\mathrm{is}\mathrm{always}a\mathrm{non}-\mathrm{negative}\mathrm{number}.x^2\mathrm{takes}\mathrm{value}0\mathrm{when}x=0.\mathrm{As}0\in [-3,5],\mathrm{the}\mathrm{minimum}\mathrm{value}\mathrm{of}{x}^2\mathrm{is}0.$