The minimum value of y, where y= 25x square - 10x + 5, is

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y = 25 x^{2} + 5 - 10 x

z = 10 x + 25 y

0 \leq x \leq 3, 0 \leq y \leq 3, x + y \geq 5

y = 5 x^{2} - 10 x

y = \frac{\sqrt{x - 25}}{x + 5}

Find the minimum and maximum value of the function y =x cube - 3x square + 6 find the values of y at which it occurs

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