The minimum velocity (in $m s^{- 1}$ ) with which a car driver must traverse a flat curve of radius $150 m$ and coefficient of friction $0.6$ to avoid skidding is

15

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30

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25

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60

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Solution

The correct option is B $30$
$v = \sqrt{μ r g}$
$v = \sqrt{0.6 \times 150 m \times 10}$
$v = 30$

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The maximum velocity (in $m s^{- 1}$ ) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is

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and coefficient of friction

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, to avoid the skidding off his car is (take

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. The smallest possible coefficient of static friction between the tyres and the road is

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The minimum velocity (in ms−1) with which a car driver must traverse a flat curve of radius 150m and coefficient of friction 0.6 to avoid skidding is

The correct option is B 30v=√μrgv=√0.6×150m×10v=30

The minimum velocity (in $m s^{- 1}$ ) with which a car driver must traverse a flat curve of radius $150 m$ and coefficient of friction $0.6$ to avoid skidding is

The correct option is B $30$
$v = \sqrt{μ r g}$
$v = \sqrt{0.6 \times 150 m \times 10}$
$v = 30$