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Introduction

The minimum v...

Question

The minimum velocity of capillary waves on the surface of water is (surface tension of water $= 7.2 \times 10^{- 2} N / m$ )

0.23 m/s

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0.46 m/s

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0.69 m/s

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0.92 m/s

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Solution

The correct option is A 0.23 m/s
Minimum velocity is given by $v_{m i n} = \sqrt{2 {(\frac{T g}{ρ})}^{1 / 2}} = 1.414 {(\frac{T g}{ρ})}^{1 / 4}$
Given : $T = 7.2 \times 10^{- 2} N / m$ , $ρ = 10^{3} k g / m^{3}$
$v_{m i n} = 1.414 {(\frac{7.2 \times 10^{- 2} \times 9.8}{10^{3}})}^{1 / 4}$
$⟹ v_{m i n} = 0.23 m / s$

Suggest Corrections

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