The minute hand when it moves $330 °$ from $11$ o'clock, is now at ?

$9 O' clock$

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$11 O' clock$

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$12 O' clock$

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$10 O' clock$

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Solution

The correct option is D
$10 O' clock$

We know,
$360 d e g r e e = 60 m i n u t e s 1 d e g r e e = \frac{60}{360} m i n u t e s O n m u l t i p l y i n g b y 330 t o b o t h s i d e 330 d e g r e e s = \frac{60}{360} \times 330 m i n u t e s 330 d e g r e e s = 55 m i n u t e s$
So the minute hand will be at $10 O' clock$ .
Hence option D is the correct answer.

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The minute hand when it moves 330° from 11 o'clock, is now at ?

The correct option is D 10O'clockWe know,360degree=60minutes1degree=60360minutesOnmultiplyingby330tobothside330degrees=60360×330minutes330degrees=55minutesSo the minute hand will be at 10O'clock.Hence option D is the correct answer.

The minute hand when it moves $330 °$ from $11$ o'clock, is now at ?