Question

The missing number in the magic square is .

• A. 1$\frac{2}{3}$
• B. 1$\frac{3}{2}$
• C. 1$\frac{4}{3}$

Answer 1

The correct option is A 1$\frac{2}{3}$

In a magic square, the sum of the numbers in each row, column and diagonal of the square is the same.

Consider, the second row, here the sum of the numbers is $2\frac{2}{3}+1\frac{1}{2}+\frac{1}{3}=\frac{9}{2}=4\frac{1}{2}$, in third row it is also $4\frac{1}{2}$, in columns also the sum of the numbers in first and third is $4\frac{1}{2}$. In both the diagonal also the sum of the numbers is $4\frac{1}{2}$

Now,
The missing number is
$=\frac{9}{2}-\frac{1}{2}-\frac{7}{3}$
$=4-\frac{7}{3}$
$=\frac{12-7}{3}$
$=\frac{5}{3}$
$=1\frac{2}{3}$