Question

The mixture of dihydrogen and dioxygen at 1 bar pressure contains 20% by weight of dihydrogen calculate the partial pressure of dihydrogen

Answer 1

Pressure of the gas mixture = 1 bar

Let us consider 100g of the mixture

So ,mass of hydrogen in the mixture = 20 g

& mass of oxygen in the mixture = 80 g

Using the respective molar masses, we get

n_H = 20/ 2 = 10 mol

. n_O = 80 / 32 = 2.5 mol

Then, p_H = X_H x P_total

= (n_H / n_{H +} n_O) x P _total

= (10 / 10 + 2.5 ) x 1

= 0.8 bar

Hence, the partial pressure of dihydrogen is 0.8 bar.