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Question

The mobility of free electrons (charge =e, mass = m and-relaxation time $$\tau$$) in a metal is proportional to :


A
emτ
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B
meτ
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C
emτ
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D
meτ
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Solution

The correct option is D $$\dfrac{e}{m}\tau $$
Drift velocity per unit electric field is called mobility of electron, i.e., $$\mu =\dfrac{V_d}{E}=\dfrac{E}{\rho neE}$$
Now, $$ \rho =\dfrac{m}{ne^2\tau }$$
$$\therefore \mu =\dfrac{ne^2\tau }{mne}=\dfrac{e\tau }{m}$$

Physics

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