The mode of the following frequency distribution is

Class Interval Frquency

0-10 4

10-20 6

20-30 8

30-40 10

40-50 7

50-60 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 34
Here, the highest frequency is 10.
Thus, the modal class is 30 - 40.
Here,
Lower limit of modal class (l) = 30
Class size (h) = 40 – 30 = 10
Frequency of the modal class $(f_{1})$ = 10
Frequency of the class preceding to the modal class $(f_{0})$ = 8 Frequency of the class succeeding to the modal class $(f_{2})$ = 7
$∴ M o d e = l + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h$
$= 30 + [\frac{10 - 8}{2 \times 10 - 8 - 7}] \times 10$
$= 30 + (\frac{2}{5} \times 10)$
$= 34$
Hence, the correct answer is option c.

Suggest Corrections

Similar questions

22

10 > y > x

y =

Class interval	0-10	10-20	20-30	30-40	40-50	Total
Frequency	5	8	10	x	y	30

31.4

x

Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$
Frequency	$5$	$x$	$10$	$12$	$7$	$8$

Class-interval:	0−10	10−20	20−30	30−40	40−50	50−60	60−70	70−80
Frequency:	5	8	7	12	28	20	10	10

Class-interval:	10−15	15−20	20−25	25−30	30−35	35−40
Frequency:	30	45	75	35	25	15

Class-interval:	25−30	30−35	35−40	40−45	45−50	50−55
Frequency:	25	34	50	42	38	14

Class:	0−10	10−20	20−30	30−40	40−50	50−60	60–70
Frequency:	8	10	10	16	12	6	7

Find the mean, mode and median of the following frequency distribution. [CBSE 2010]

Class	0−10	10−20	20−30	30−40	40−50	50−60	60−70
Frequency	4	4	7	10	12	8	5

25

p

Class interval	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
Frequency	$5$	$18$	$15$	$p$	$6$

Join BYJU'S Learning Program