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Question

The modulus and amplitude of 1+2i1−(1−i)2 are ____

A
2 and π6
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B
1 and π6
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C
1 and 0
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D
1 and π3
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Solution

The correct option is C 1 and 0
Given that: 1+2i1(1i)2
=1+2i1(12i1)
=1+2i1(2i)
=1+2i1+2i
=1
=ei0
Hence modulus is 1 while amplitude is 0.

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