The modulus and amplitude of (1+i√3)8 are respectively
A
256 and π3
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B
256 and 2π3
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C
2 and 2π3
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D
256 and 8π3
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Solution
The correct option is B256 and 2π3 Let z=(1+i√3)8 =(−2)8(1+i√3−2)8 =(−2)8(ω2)8 =28ω16 =28ω(∵ω3=1) =28(−1+i√32) =28(cos2π3+isin2π3) Therefore, modulus =28=256 and amplitude =2π3