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Question

The modulus of 1i3+i+4i5 is

A
5 unit
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B
115 unit
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C
55 unit
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D
125 unit
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Solution

The correct option is D 55 unit
Let z=1i3+i+4i5
=55i+12i45(3+i)=1+7i5(3+i)
=(1+7i)(3i)5(9+1)
=10+20i50=1+2i5
|z|=(15)2+(25)2=151+4=52

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