Question

The molal depression constant for water is ${1.86}^{\circ }C$. The freezing point of a 0.05-molal solution of a non-electrolyte in water is

• A. $-{1.86}^{\circ }C$
• B. $-{0.93}^{\circ }C$
• C. $-{0.093}^{\circ }C$
• D. $-{0.93}^{\circ }C$

Answer 1

The correct option is C $-{0.093}^{\circ }C$

$\Delta Tf=Kf\times Molality=1.86\times 0.05=0.093$
Thus, freezing point = $0-0.093=-{0.093}^{\circ }C$