Question

The molality of $1$ L solution with $x\%$ $H_{2}S{O}_4$ is $9$. The weight of the solvent present in the solution is $910$ g. The value of $x$ is:

• A. $90$
• B. $49$
• C. $30$
• D. $47$

Answer 1

The correct option is B $49$

$1$ L of solution contains $9$ moles of sulfuric acid which corresponds to $9\times 98=882$ g.
$1$ L of solution contains $910$ g water.
Hence, the percentage of sulphuric acid in the solution is $\frac{882}{882+910}\times 100=49.2$%.