The molality of 98 - H 3 P O 4 by weight is -A- 50 mB- 25 mC- 500 mD- 250 m

The correct option is C 500 mAssuming 100 g of the solution, mass of nbsp; the acid is 98 g since % w/w=98%. Molar mass of the acid, M=98 g mol^ 1 mass of t ...

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Standard XII

Chemistry

Mole Concept

The molality ...

Question

The molality of $98 %$ $H_{3} P O_{4}$ by weight is :

50 m

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500 m

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250 m

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25 m

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Solution

The correct option is B 500 m
Assuming 100 g of the solution, mass of the acid is 98 g since $% w / w = 98 %$ .

Molar mass of the acid, $M = 98 {g mol}^{- 1}$
mass of the solvent = 2 g
$Molality = \frac{moles}{Mass of solvent in kg} = \frac{1}{0.002} = 500 m$

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The molality of 98% H3PO4 by weight is :

The correct option is B 500 mAssuming 100 g of the solution, mass of the acid is 98 g since % w/w=98%. Molar mass of the acid, M=98 g mol−1 mass of the solvent = 2 g Molality=molesMass of solvent in kg=10.002=500 m

The molality of $98 %$ $H_{3} P O_{4}$ by weight is :

The correct option is B 500 m
Assuming 100 g of the solution, mass of the acid is 98 g since $% w / w = 98 %$ .

Molar mass of the acid, $M = 98 {g mol}^{- 1}$
mass of the solvent = 2 g
$Molality = \frac{moles}{Mass of solvent in kg} = \frac{1}{0.002} = 500 m$