The molality of a solution in water is 10 m. Calculate mole fraction of the solute given the molar mass of the solute is 38.8 $g m o l^{- 1}$ and molar mass of the solvent = 25 $g m o l^{- 1}$

0.1

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0.25

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Solution

The correct option is C
0.2
Given information:
Molality of the solution = 10 m ( 10 moles in 1 kg of the solvent)
Number of moles in 100 g of the solvent = 1
Number moles of solvent = $\frac{100}{25}$ = 4
Mole fraction of the solute = $\frac{moles of the solute}{total moles of the solution}$
= $\frac{1}{5}$ = 0.2

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The molality of a solution in water is 10 m. Calculate mole fraction of the solute given the molar mass of the solute is 38.8 gmol−1 and molar mass of the solvent = 25 gmol−1

The correct option is C 0.2Given information: Molality of the solution = 10 m ( 10 moles in 1 kg of the solvent) Number of moles in 100 g of the solvent = 1 Number moles of solvent = 10025 = 4 Mole fraction of the solute =moles of the solutetotal moles of the solution = 15 = 0.2

The molality of a solution in water is 10 m. Calculate mole fraction of the solute given the molar mass of the solute is 38.8 $g m o l^{- 1}$ and molar mass of the solvent = 25 $g m o l^{- 1}$