Question

The molality of a sulphuric acid solution is $0.2$. Calculate the total weight having $1000gm$ of solvent.

• A. $1000g$
• B. $1098.6g$
• C. $980.4g$
• D. $1019.6g$

Answer 1

The correct option is D $1019.6g$

Molality= $\frac{\text{Number of moles of solute}}{\text{kg solvent}}$

$0.2$ moles are present in $1kg$ of solvent.

Mass of solution= Mass of solute $+$ Mass of solvent

Mass of solute= $98\times 0.2=19.6g$

$\therefore$ Mass of solution= $1000+19.6=1019.6g$