Question

The molality of a sulphuric acid solution is 0.2 mol/kg. Calculate the total weight of the solution having 1000 g, of solvent:-

• A. 1000 g
• B. 1098.6 g
• C. 980.4 g
• D. 1019.6 g

Answer 1

The correct option is D 1019.6 g

Given, molality (m) = 0.2 mol/kg
weight of solvent = 1000 g
Since it is a sulphuric acid ($H_{2}S{O}_4$) solution weight of solute $=0.2\times 98=19.6g$
Total weight of solution will be $=1000+19.6=1019.6g$