Question

The molar conductance of $0.001M$ acetic acid is $50oh{m}^{-1}c{m}^{2}mo{l}^{-1}$. The maximum value of molar conductance of acetic acid is $250oh{m}^{-1}c{m}^{2}mo{l}^{-1}$. What is the degree of dissociation $\left(\alpha \right)$ of acetic acid?

• A. $0.5$
• B. $0.2$
• C. $0.3$
• D. $0.4$

Answer 1

The correct option is B $0.2$

Conc. = 0.01 M

${\lambda }_m$ = 50

${\lambda }_m^o$ = 250

degree of dissociation $\alpha$ = {${\lambda }_m$} $\frac{1}{{\lambda }_m^o}$

$\alpha$ = $\frac{50}{250}$

$\alpha$ = 0.2