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Standard XII

Chemistry

Conductance and Conductivity

The molar con...

Question

The molar conductance of $N H_{4} O H$ at 0.01M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation
of $N H_{4} O H$ is
(molar conductance at infinite dilution is 271.1)
$4.2 %$

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Solution

The correct option is A $4.2 %$
$α = \frac{11.3}{271.1}$ = 0.042 or 4.2 $%$

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The molar conductance of $N H_{4} O H$ at 0.01 M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation of $N H_{4} O H$ is: (Molar conductance at infinite dilution = 271.1 $o h m^{- 1} c m^{2} m o l^{- 1}$

Q. The molar conductance of

N H_{4} O H

at 0.01M concentration is 11.3

o h m^{- 1} c m^{2} m o l^{- 1}

. The degree of dissociation
of

N H_{4} O H

is
(molar conductance at infinite dilution is 271.1)

Q. The molar conductance of

N H_{4} O H

at 0.01M concentration is 11.3

o h m^{- 1} c m^{2} m o l^{- 1}

. The degree of dissociation
of

N H_{4} O H

is
(molar conductance at infinite dilution is 271.1)

Q. A

0.05 M

N H_{4} O H

solution offers the resistance of

50 o h m

to a conductivity cell at

298 K

. If the cell constant is

0.50 {c m}^{- 1}

and molar conductance of

N H_{4} O H

at infinite dilution is

471.4 {o h m}^{- 1} {c m}^{2} {m o l}^{- 1}

, calculate :

(i) Specific conductance
(ii) Molar conductance
(iii) Degree of dissociation

Q. At

25^{\circ} C

molar conductance of

0.1

molar aqueous solution of ammonium hydroxide is

9.52

{ohm}^{- 1} {cm}^{2} {mol}^{- 1}

and at infinite dilution its molar conductance is

238

{ohm}^{- 1} {cm}^{2} {mol}^{- 1}

. The percentage degree of dissociation of ammonium hydroxide at the same concentration and temperature is:
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The molar conductance of NH4OH at 0.01M concentration is 11.3 ohm−1 cm2 mol−1. The degree of dissociation of NH4OH is (molar conductance at infinite dilution is 271.1)4.2%

The correct option is A 4.2%α=11.3271.1 = 0.042 or 4.2 %

The molar conductance of $N H_{4} O H$ at 0.01M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation
of $N H_{4} O H$ is
(molar conductance at infinite dilution is 271.1)
$4.2 %$

The correct option is A $4.2 %$
$α = \frac{11.3}{271.1}$ = 0.042 or 4.2 $%$