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Byju's Answer

Standard XII

Chemistry

Conductance and Conductivity

The molar con...

Question

The molar conductance of $N H_{4} O H$ at 0.01M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation
of $N H_{4} O H$ is
(molar conductance at infinite dilution is 271.1)

4.2 %

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1.3 %

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12.6 %

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41 %

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Solution

The correct option is A $4.2 %$
$α = \frac{11.3}{271.1}$ = 0.042 or 4.2 $%$

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Similar questions

Q. The molar conductance of

N H_{4} O H

at 0.01M concentration is 11.3

o h m^{- 1} c m^{2} m o l^{- 1}

. The degree of dissociation
of

N H_{4} O H

is
(molar conductance at infinite dilution is 271.1)

Q. The molar conductance of

N H_{4} O H

at 0.01M concentration is 11.3

o h m^{- 1} c m^{2} m o l^{- 1}

. The degree of dissociation
of

N H_{4} O H

is
(molar conductance at infinite dilution is 271.1)

The molar conductance of $N H_{4} O H$ at 0.01 M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation of $N H_{4} O H$ is: (Molar conductance at infinite dilution = 271.1 $o h m^{- 1} c m^{2} m o l^{- 1}$

Q. The conductivities at infinite dilution of

N H_{4} C l, N a O H

and

N a C l

are

130, 218, 120

o h m^{- 1}

c m^{2}

e q^{- 1}

. If equivalent conductance of

\frac{N}{100}

solution of

N H_{4} O H

10

o h m^{- 1}

c m^{2}

e q^{- 1}

, then degree of dissociation of

N H_{4} O H

at this dilution is:

Q. A

0.05 M

N H_{4} O H

solution offers the resistance of

50 o h m

to a conductivity cell at

298 K

. If the cell constant is

0.50 {c m}^{- 1}

and molar conductance of

N H_{4} O H

at infinite dilution is

471.4 {o h m}^{- 1} {c m}^{2} {m o l}^{- 1}

, calculate :

(i) Specific conductance
(ii) Molar conductance
(iii) Degree of dissociation

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The molar conductance of NH4OH at 0.01M concentration is 11.3 ohm−1 cm2 mol−1. The degree of dissociation of NH4OH is (molar conductance at infinite dilution is 271.1)

The correct option is A 4.2%α=11.3271.1 = 0.042 or 4.2 %

The molar conductance of $N H_{4} O H$ at 0.01M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation
of $N H_{4} O H$ is
(molar conductance at infinite dilution is 271.1)

The correct option is A $4.2 %$
$α = \frac{11.3}{271.1}$ = 0.042 or 4.2 $%$