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Question
The molar conductance of sodium acetate(CH3COONa), hydrochloric acid(HCl) and sodium chloride(NaCl) at infinite dilution are 91.0×10−4,426.16×10−4 and 126.45×10−4 S m2 mol−1 respectively, at 25∘C. Calculate the molar conductance at infinite dilution of for acetic acid:
The molar conductance of sodium acetate(CH3COONa), hydrochloric acid(HCl) and sodium chloride(NaCl) at infinite dilution are 91.0×10−4,426.16×10−4 and 126.45×10−4 S m2 mol−1 respectively, at 25∘C. Calculate the molar conductance at infinite dilution of for acetic acid:
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Solution
The correct option is B 390.71×10−4 S m2 mol−1
Λ∘mCH3COONa=λ∘CH3COO−+λ∘Na+=91.0×10−4 S m2 mol−1
Λ∘mHCl=λ∘H++λ∘Cl−=426.16×10−4 S m2 mol−1
Λ∘mNaCl=λ∘Na++λ∘Cl−=126.45×10−4 S m2 mol−1
λ∘CH3COO−+λ∘H+=λ∘CH3COO−+λ∘Na++λ∘H++λ∘Cl−−λ∘Na+−λ∘Cl−
or
Λ∘mCH3COOH=Λ∘mCH3COONa+Λ∘mHCl−Λ∘mNaCl
=(91.00+426.16−126.45)×10−4=390.71×10−4 S m2 mol−1
Λ∘mCH3COONa=λ∘CH3COO−+λ∘Na+=91.0×10−4 S m2 mol−1
Λ∘mHCl=λ∘H++λ∘Cl−=426.16×10−4 S m2 mol−1
Λ∘mNaCl=λ∘Na++λ∘Cl−=126.45×10−4 S m2 mol−1
λ∘CH3COO−+λ∘H+=λ∘CH3COO−+λ∘Na++λ∘H++λ∘Cl−−λ∘Na+−λ∘Cl−
or
Λ∘mCH3COOH=Λ∘mCH3COONa+Λ∘mHCl−Λ∘mNaCl
=(91.00+426.16−126.45)×10−4=390.71×10−4 S m2 mol−1
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