The molar conductance of sodium acetateCH3COONa- hydrochloric acidHCl and sodium chlorideNaCl at infinite dilution are 91-0 - 10-4- 426-16- 10-4 and 126-45- 10-4 S m2 mol-1 respectively- at 25-C- Calculate the molar conductance at infinite dilution of for acetic acid-

Λ ^∘_mCH_3COONa=λ ^∘_CH_3COO^ +λ ^∘_Na^+ = 91.0 × 10^ 4 S m^2 mol^ 1 nbsp; Λ ^∘_mHCl=λ ^∘_H^+ + λ ^∘_Cl^ =426.16 nbsp;× 10^ 4 S m^2 mol^ 1 nbsp; Λ ^∘_mN ...

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Standard IX

Chemistry

Kohlrausch Law

The molar con...

Question

The molar conductance of sodium acetate $(C H_{3} C O O N a)$ , hydrochloric acid $(H C l)$ and sodium chloride $(N a C l)$ at infinite dilution are $91.0 \times 10^{- 4}, 426.16 \times 10^{- 4} and 126.45 \times 10^{- 4} S m^{2} m o l^{- 1}$ respectively, at $25^{\circ} C$ . Calculate the molar conductance at infinite dilution of for acetic acid:

290.62 \times 10^{- 4} S m^{2} m o l^{- 1}

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390.71 \times 10^{- 4} S m^{2} m o l^{- 1}

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280.00 \times 10^{- 4} S m^{2} m o l^{- 1}

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300.45 \times 10^{- 4} S m^{2} m o l^{- 1}

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Solution

The correct option is B $390.71 \times 10^{- 4} S m^{2} m o l^{- 1}$
$Λ_{m C H_{3} C O O N a}^{\circ} = λ_{C H_{3} C O O^{-}}^{\circ} + λ_{N a^{+}}^{\circ} = 91.0 \times 10^{- 4} S m^{2} m o l^{- 1}$
$Λ_{m H C l}^{\circ} = λ_{H^{+}}^{\circ} + λ_{C l^{-}}^{\circ} = 426.16 \times 10^{- 4} S m^{2} m o l^{- 1}$
$Λ_{m N a C l}^{\circ} = λ_{N a^{+}}^{\circ} + λ_{C l^{-}}^{\circ} = 126.45 \times 10^{- 4} S m^{2} m o l^{- 1}$
$λ_{C H_{3} C O O^{-}}^{\circ} + λ_{H^{+}}^{\circ} = λ_{C H_{3} C O O^{-}}^{\circ} + λ_{N a^{+}}^{\circ} + λ_{H^{+}}^{\circ} + λ_{C l^{-}}^{\circ} - λ_{N a^{+}}^{\circ} - λ_{C l^{-}}^{\circ}$
$or$
$Λ_{m C H_{3} C O O H}^{\circ} = Λ_{m C H_{3} C O O N a}^{\circ} + Λ_{m H C l}^{\circ} - Λ_{m N a C l}^{\circ}$
$= (91.00 + 426.16 - 126.45) \times 10^{- 4} = 390.71 \times 10^{- 4} S m^{2} m o l^{- 1}$

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Similar questions

Q. The equivalent conductances of sodium choride, hydrochloric acid and sodium acetate at infinite dilution are

126.45, 426.16

and

91.0 o h m^{- 1} c m^{2} e q^{- 1}

, respectively, at

25^{\circ} C

. Calculate the equivalent conductance of acetic acid at infinite dilution.

Q. The equivalence conductances of sodium chloride, hydrochloric acid and sodium acetate at infinite dilution are

126.45, 426.16

and

91.0 {ohm}^{- 1} {cm}^{2} {eq}^{- 1}

, respectively at

25^{o} C

.
Calculate the equivalent conductance

({in ohm}^{- 1} {cm}^{2} {eq}^{- 1})

of acetic acid at infinite dilution.

Q. The molar conductance of

N a C l, H C l

and

C H_{3} C O O N a

at infinite dilution are

126.45, 426.16

and

91.0 S c m^{2} m o l^{- 1}

respectively. The molar conductance of

C H_{3} C O O H

at infinite dilution is.
Choose the right option for your answer.

Q. The specific conductance of

0.01 M

solution of acetic acid was found to be

0.0163 S m^{- 1}

25 ° C

. Calculate the degree of dissociation of the acid. Molar conductance of acetic acid at infinite dilution is

390.7 \times 10^{- 4} S m^{2} m o l^{- 1}

25 ° C

Q. At

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, the specific conductance of

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aqueous solution of acetic acid is

1.63 \times 10^{- 2} S m^{- 1}

and the molar conductance at infinite dilution is

390.7 \times 10^{- 4} S m^{2} m o l^{- 1}

. Calculate the dissociation constant

(K_{a})

of the acid.

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The molar conductance of sodium acetate(CH3COONa), hydrochloric acid(HCl) and sodium chloride(NaCl) at infinite dilution are 91.0×10−4,426.16×10−4 and 126.45×10−4 S m2 mol−1 respectively, at 25∘C. Calculate the molar conductance at infinite dilution of for acetic acid: